7c^2-21c+14=0

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Solution for 7c^2-21c+14=0 equation:


Simplifying
7c2 + -21c + 14 = 0

Reorder the terms:
14 + -21c + 7c2 = 0

Solving
14 + -21c + 7c2 = 0

Solving for variable 'c'.

Factor out the Greatest Common Factor (GCF), '7'.
7(2 + -3c + c2) = 0

Factor a trinomial.
7((1 + -1c)(2 + -1c)) = 0

Ignore the factor 7.

Subproblem 1

Set the factor '(1 + -1c)' equal to zero and attempt to solve: Simplifying 1 + -1c = 0 Solving 1 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1c = 0 + -1 -1c = 0 + -1 Combine like terms: 0 + -1 = -1 -1c = -1 Divide each side by '-1'. c = 1 Simplifying c = 1

Subproblem 2

Set the factor '(2 + -1c)' equal to zero and attempt to solve: Simplifying 2 + -1c = 0 Solving 2 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1c = 0 + -2 -1c = 0 + -2 Combine like terms: 0 + -2 = -2 -1c = -2 Divide each side by '-1'. c = 2 Simplifying c = 2

Solution

c = {1, 2}

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